Home
Class 12
CHEMISTRY
Gold (atomic radius = 0.144 nm) crystall...

Gold (atomic radius = 0.144 nm) crystallises in a face centred unit cell. What is the length of the side of the cell?

Text Solution

Verified by Experts

For fac unit cell, `a=(2sqrt(2)) xx r`
`=2xx1.44 xx 0.144=0.407`nm
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART II (QUESTION FOR PRACTICE) (Short Answer Type I Questions)|14 Videos

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART II (QUESTION FOR PRACTICE) (Short Answer Type II Questions)|9 Videos

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART II (QUESTION FOR PRACTICE) (Multiple Choice Type Questions)|5 Videos

  • SURFACE CHEMISTRY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( LONG ANSWER TYPE QUESTIONS)|1 Videos

Similar Questions

Explore conceptually related problems

What is a face-centred cubic unit cell?

Aluminium crystallises in a fcc structure. Atomic radius of the metal is 125 pm. What is the length of the side of the unit cell of the metal?

Calcium metal crystallises in a face centred cubic lattice with edge length of 0.556 nm. Calculate the density of the metal if it contains (i) 0.2% Frenkel defects (ii) 0.1% Schottky defects

What is unit cell ?