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An element with density 2.8 g cm^(-3) fo...

An element with density 2.8 g `cm^(-3)` forms fcc unit cell with edge length `4 xx 10^(-8)` cm. Calculate the molar mass of the element.
(Given, `N_(A)=6.022 xx 10^(23)"mol"^(-1)`)

Text Solution

Verified by Experts

Given that, density d= 2.8 g `cm^(-3)`
Edge length, `a=4xx10^(-8)`cm
For fcc, Z=4
Applying the formula,
`d=(ZM)/(a^(3)N_(A))`
`:. M=(da^(3)N_(A))/(Z)`
`=(2.8g cm^(-3) xx (4xx10^(-8)cm)^(3) xx 6.022 xx 10^(23) "mol"^(-1))/(4)`
`M= 26.98=27 "g mol"^(-1)`
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