Home
Class 12
CHEMISTRY
An element with density 11.2 g cm^(-3) ...

An element with density 11.2 g `cm^(-3)` forms a fcc lattice with edge length of `4 xx 10^(-8)` cm.
Calculate the atomic mass of the element.
(Given, `N_(A)=6.022 xx 10^(23)"mol"^(-1)`)

Text Solution

Verified by Experts

Given that density, `d=11.2 g cm^(-3)`
Edge length, `a=4xx10^(-8)cm`
For fcc, `Z=4`
`:. d=(Z xx M)/(a^(3)xx N_(A))`
`:. M=(d xx a^(3)xx N_(A))/(Z)`
`=(11.2 g cm^(-3) xx (4xx10^(-8)cm)^(3) xx 6.022 xx 10^(23)"mol"^(-1))/(4)`
`=107.9~~108"g mol"^(-1)`
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART II (QUESTION FOR PRACTICE) (Short Answer Type II Questions)|9 Videos

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART II (QUESTION FOR PRACTICE) (Long Answer Type Questions)|2 Videos

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise PART II (QUESTION FOR PRACTICE) (Very Short Answer Type Questions)|11 Videos

  • SURFACE CHEMISTRY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( LONG ANSWER TYPE QUESTIONS)|1 Videos

Similar Questions

Explore conceptually related problems

An element occurs in b c c structure with cell edge of 288 p m .Its density is 7.2 g cm^-3 . calculate the atomic mass of the element.

Silver crystallises in fcc lattice. If edge length of the cell is 4.07xx10^(-8) and density is 10.5 g cm^(-3) . Calculate the atomic mass of silver.

An element with molar mass 27 g "mol"^(-1) forms a cubic unit cell with edge length 4.05 xx 10^(-8) cm. If its density is 2.7 g cm^(-3) , what is the nature of the cubic unit cell?

The density of copper is 17.90 gcm^(-3) . It has a fcc structure. What is the radius of copper atom? (Atomic mass oCu = 63.5 "g mol"^(-1),N_(A)=6.02xx10^(23)"mol"^(-1) ]

Copper crystallises into a fcc lattice with edge length 3.61xx10^(-8) cm. Show that the calculated density of Cu is in agreement with its measured value of 8.92 g cm^(-3) .