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For a reaction, P to Q, the rate becomes...

For a reaction, `P to Q`, the rate becomes 8 times when concentration of P is doubled. What is the order of the reaction?

Text Solution

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Let `r = k [P]^(n)" "...(i)`
`8r = k [2P]^(n)" "...(ii)`
On dividing Eq. (ii) by Eq. (i), we get
`(8r)/( r) = ( k [2P]^(n) )/( k[P]^(n) )` or ` [2]^(3)` or `n=3`
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