Radioactive decay is a first order rate process. Two-third of a radioactive isotope disintegrates in 30 min. What is the rate constant of the disintegration?

Explanation

For first order reaction, `t= (2.303)/( k) log"" (a)/( a-x)`
Given, `(a-x) = (a- (2a)/(3) ) = (1)/(3) a`
`therefore k = (2.303)/( 30) log"" (a)/( 1//3a) = (2.303)/( 30) log 3 = 0.03663" min"^(-1)`