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A certain reaction is 50% complete in 20...

A certain reaction is 50% complete in 20 min at 300 K and the remaining of the reaction is again 50% complete in 5 min at 350 K. Calculate the activation energy if it is a first order reaction.
`(R = 8.314"JK"^(-1)" mol"^(-1), log 4= 0.602)`

Text Solution

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The correct Answer is:
`24.21"kJ mol"^(-1)`
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