`XeOF_(4)`

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Write down the structure of XeO_(4)andXeF_(4) .

If K_1 and K_2 are the respective equiliberium constant for the two reactions XeF_6 (g) + H_2O(g) = XeOF_4 (g) + 2HF(g) XeO_4 (g) + XeF_6 (g) ⇌ XeOF_4 (g) XeO_3F_2(g ) , The equiliberium constant for the reaction, XeO_4 (g) + 2HF (g) ⇌ XeO_3F_2 + H_2O (g ) is :

Give the shape of XeOF_2

MnO_(4)^(2-) can be converted to MnO_(4)^(-)