Home
Class 12
CHEMISTRY
When sodium salt of ethanol is treated w...

When sodium salt of ethanol is treated with ehtyl bromide, the product formed is

A

methoxy ethane

B

ethoxy ethanol

C

methyl ethyl ketone

D

diethyl ether

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • HALOALKANES (ALKYL HALIDE)

    ARIHANT PUBLICATION|Exercise PART-II- QUESTION FOR PRACTICE (VERY SHORT ANSWER TYPE QUESTIONS)|9 Videos
  • HALOALKANES (ALKYL HALIDE)

    ARIHANT PUBLICATION|Exercise PART-II- QUESTION FOR PRACTICE (SHORT ANSWER TYPE I QUESTIONS)|19 Videos
  • HALOALKANES (ALKYL HALIDE)

    ARIHANT PUBLICATION|Exercise PART-I- QUESTIONS FOR ASSESSMENT (LONG ANSWER TYPE QUESTIONS)|1 Videos
  • GROUP 18 ELEMENTS NOBLEGASES

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( Long Answer Type Questions )|6 Videos
  • PHENOLS

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE (Long Answer Type Questions )|1 Videos

Similar Questions

Explore conceptually related problems

When sodium benzene sulphonate is fused with sodium hydroxide the product formed is

When sodium salt of benzoic acid is heated with sodalime produces_____.

Knowledge Check

  • When benzene diazonium chloride is treated with cuprous chloride and HCl the product formed is :

    A
    Chlorobenzene
    B
    Benzene
    C
    Phenol
    D
    Chloroazobenzene
  • When methyl iodide is treated with ammonia, the product obtained is :

    A
    Methylamine
    B
    Dimethylamine
    C
    Trimethylamine
    D
    All
  • When isopropyl iodide in ethereal solution is warmed with sodium, the product formed is

    A
    n-hexane
    B
    neo-hexane
    C
    2, 3-dimethylbutane
    D
    All of these
  • Similar Questions

    Explore conceptually related problems

    What happens when methyl amine is treated with methyl bromide.

    When sodium salt of acetic acid reacts with soda lime ____ is produced.

    When isopropyl iodide in ethereal solution is warmed with sodium, the product formed is

    When CH_3CH_2CH Cl_2 is treated with NaNH_2 , the product formed is:

    When CH_3CH_2CH Cl_2 is treated with NaNH_2 , the product formed is: