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Let A = { x:x in R ,(-pi)/(2) lt= xlt= (...

Let A `= { x:x in R ,(-pi)/(2) lt= xlt= (pi)/(2)}` and B =`(y:y in R , -1 lt= y lt=1}` . Show that the function f : A `rarr` B given by f(x) = sin x is invertible andc hence find `f^(-1)` .

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The correct Answer is:
`sin^(-1) ` y
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