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For vec(a) = hat(i) - hat(j), vec(b) = h...

For `vec(a) = hat(i) - hat(j), vec(b) = hat(i) - 2hat(k)` and `vec(c) = hat(j) + hat(k)`, obtain `vec(a) xx (vec(b) xx vec(c))` `.

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The correct Answer is:
`[(vec(a).vec(c))vec(b) - (vec(a).vec(b))vec(c)]`
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