Calculate `K_c` for the reversible process given below
`K_p=167`, and `T = 800^@C`
`CaCO_(3(s)) harr CaO_((s)) + CO_(2(g))`

Options

A. 1.95
B. 1.85
C. 1.89
D. 1.6

Answer

C

Explanation

`K_p=K_c(RT)Delta n_g`
For equation, `CaCO_(3(g)) harr CaO_((g))+CO_(2(g)), Deltan=1` T=800+273=1073 K
`K_c=(K_p)/((RT)^(Delta n_g))=(167)/((0.0821xx1073)^(1))=1.89`