The solubility product of a sparingly soluble salt `AB` at room temperature is `1.21xx10^(-6)`. Its molar solubility is

Options

A. `1.1 xx 10^(-3) mol L^(-1)`
B. `1.21 xx 10^(-6) mol L^(-1)`
C. `1.01 xx 10^(-3) mol L^(-1)`
D. `1.1 xx 10^(-4) mol L^(-1)`

Answer

A

Explanation

`underset(s)(AB) harr underset(s)(A^(+))+underset(s)(B^(-))`
`implies` Solubility product = `S xx S=S^2`
`implies s=sqrt(1.21xx10^(-6))=1.1xx10^(-3) mol L^(-1)`