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The equilibrium constant of a reaction i...

The equilibrium constant of a reaction is `0.008` at `298 K`. The standard free energy change of the reaction at the same temperture is

A

+11.96 kJ

B

-11.96 kJ

C

-5.43 kJ

D

-8.46 kJ

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG^@= -2.303RT log K, DeltaG^@=2.303xx8.314xx2(0.008), DeltaG^@= -5705. 84xx -2.09, DeltaG^@=11960 J=11.96kJ`
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