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Iron exhibits bcc structure at roomj tem...

Iron exhibits `bcc` structure at roomj temperature. Above `9000^(@)C`, it transformers to `fcc` structure. The ratio of density of iron at room temperature to that at `900^(@)C` (assuming molar mass and atomic radius of iron remains constant with temperature) is

A

`(sqrt3)/(sqrt2)`

B

`(4sqrt3)/(3sqrt2)`

C

`1/2`

D

`(3sqrt3)/(4sqrt2)`

Text Solution

Verified by Experts

The correct Answer is:
D

For bcc lattice: Z = 2, `a =(4r)/(sqrt3)`
For fcc lattice: Z=4. `a = 2sqrt2 r`
`:. (d_(25^@C))/(d_(900^@C))=(((ZM)/(N_A a^3))_(b c c))/(((ZM)/(N_A a^3))_(f c c))`
`=2/4 ((2sqrt2 r)/((4r)/(sqrt3)))^3=((3sqrt3)/(4sqrt2))`
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