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The molarity of a 0.2 N Na(2) CO(3) solu...

The molarity of a 0.2 N `Na_(2) CO_(3)` solution will be

A

`0.1` M

B

0 M

C

`0.4` M

D

`0.2` M

Text Solution

Verified by Experts

The correct Answer is:
A

Molarity = Normality = `("equivalent weight")/("molecular weight")`
Given , normality of `Na_(2)CO_(2)` solution = 0.2 N
Equivalent weight = M `( :. Na_(2)CO_(2) " in dipositive ")`
` :. " Molarity " = 0.2 xx M/(2M) = 0.1 M `
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