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A complex of iron and cyanide ions is 10...

A complex of iron and cyanide ions is `100%`ionised ar `1`m (molal). If its elevation in b.p.is `2.08` then the complex is `(K_(b)=0.52^(@)mol^(-1)kg)`,

A

`K_(3)[Fe(CN)_(6)]`

B

`Fe(CN)_(2)`

C

`K_(6)[Fe (CN)_(6)] `

D

`Fe(CN)_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaT_(b) = iK_(b) `m
So I `= (2.08)/(0.52 xx1) = 4`
So the complex is `K_(3) [Fe(CN_(6))] `
`K_(3) [Fe(CN)_(6)] hArr 3K^(+) + [ Fe(CN)_(6)]^(3-)`
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