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Mole fraction of C(3)H(5)(OH)(3) in a so...

Mole fraction of `C_(3)H_(5)(OH)_(3)` in a solution of 36 g of water and 46 g of glycerine is :

A

`0.46`

B

`0.36`

C

`0.20`

D

`0.42`

Text Solution

Verified by Experts

The correct Answer is:
C
Mole of `H_(2)O = 36/18 = 2 `
Mole of glycerine = `46/92 = 0.5`
Total mole = `2+ 0.5 = 2.5`
Mole fractions of glycerine = `(n_(1))/(n_(1)+n_(2)) = (0.5)/(2.5)`
`x_(0) = 0.2 `
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