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Mixture of voltaile omponents A and B ha...

Mixture of voltaile omponents A and B has total vapoure pressure (in torr) : `p=254-135 x_(A)` where `x_(A)` is mole fraction of A in mixture hence `P_(A)^(@) and P_(B)^(@)` are (in torr)

A

254, 119

B

119, 254

C

135254

D

119373

Text Solution

Verified by Experts

The correct Answer is:
C

`P = x_(A)p_(A)^(0) +x_(B)p_(B)^(0) = (p_(A)^(0) -p_(B)^(0))x_(A) +p_(B)^(0)`
So `p_(B)^(0) = 254 `
`p_(A)^(0) - p_(B)^(0) = -119 " " p_(A)^(0) = 135 , p_(B)^(0) = 254`
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