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For the tetrahedral complex [MnBr(4)]^(2...

For the tetrahedral complex `[MnBr_(4)]^(2-)`, the spin only magnetic moment value is:
[Atomic numer of Mn = 25]

A

2.4

B

1.7

C

5.9

D

4.8

Text Solution

Verified by Experts

The correct Answer is:
C
In `[MnBr_(4)]^(2-)`
`Mn^(2+)=[Ar]^(18)3d^(5)4s^(0)`,
`[MnBr_(4)]^(2+)` is tetrahedral complex

`n=5`
`mu=sqrt(n(n+2))=sqrt(5(5+2))=sqrt(5(7))=sqrt(35)`
= 5.9 B.M
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