Which one of the following is wrongly matched

Options

A. `[Cu(NH_(3))_(4)]^(2+)` = Square planar
B. `[Ni(CO)_(4)]` = Neutral ligand
C. `[Fe(CN)_(6)]^(3-)=sp^(3)d^(2)`
D. `[Co(en)_(3)]^(3+)` = Follows EAN rule

Answer

C

Explanation

`[Fe(CN)_(6)]^(3-)impliesx-6=-3`
`x=-3+6`
`x=+3`
`Fe^(3+)=26` =
CN is strong ligand, it create pairing

`therefore` The hybridisation used is `d^(2)sp^(3)`. inner orbital complete.