`CH_(3) - underset(D)underset(|)overset(H)overset(|)(C) - CHO overset(dil.NaOH)(rarr)` Product. The product of this reaction would be :

Options

A. `CH_(2) - underset(CHO)underset(|)overset(D)overset(|)(C) - overset(OH)overset(|)(CH) - underset(D)underset(|)(CH) - CH_(2)`
B. `CH_(2) - underset(CHO)underset(|)overset(H)overset(|)(C) - overset(OH)overset(|)(CH) - underset(D) underset(|)(CH) - CHO`
C.
D. `CH_(2) - underset(H)underset(|)overset(CHO)overset(|)(C) - CH - underset(OH)underset(|)overset(D)overset(|)(CH) - CHO`

Explanation

To solve the given question, we need to analyze the reaction of the compound CH3-CH(D)-C(=O)H (which is an aldehyde with a deuterium atom) with dilute NaOH. This reaction is an example of aldol condensation. Let's break down the steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactant is CH3-CH(D)-CHO. Here, CH3 is a methyl group, CH(D) indicates a carbon with a deuterium atom, and CHO is the aldehyde functional group.

2. **Recognize the Role of Dilute NaOH**:
Dilute NaOH acts as a base in this reaction. The hydroxide ion (OH-) will abstract an acidic hydrogen from the alpha carbon (the carbon adjacent to the carbonyl group).

3. **Identify the Alpha Hydrogen**:
The alpha hydrogen in this case is the hydrogen on the carbon adjacent to the carbonyl group (the CH(D) group). Since deuterium (D) is present, it can be considered as a hydrogen atom in terms of acidity, but it will affect the product structure.

4. **Formation of the Enolate Ion**:
When OH- abstracts the alpha hydrogen, it forms an enolate ion. The structure of the enolate ion will be:
\[ CH3-C(D)^{-}-C(=O)H \]
Here, the negative charge is on the alpha carbon.

5. **Nucleophilic Attack**:
The enolate ion will then attack the carbonyl carbon of another molecule of the aldehyde (CH3-CH(D)-CHO). This forms a beta-hydroxy aldehyde.

6. **Formation of the Beta-Hydroxy Aldehyde**:
The product of this step will be:
\[ CH3-CH(D)-C(OH)(CHO) \]
This is a beta-hydroxy aldehyde.

7. **Final Product**:
The aldol condensation reaction typically proceeds to dehydration (loss of water), leading to the formation of an α,β-unsaturated carbonyl compound. However, since the question does not specify further reactions, we will consider the beta-hydroxy aldehyde as the final product.

### Final Answer:
The product of the reaction is:
\[ CH3-CH(D)-C(OH)(CHO) \]