Which of the following will not undergo Hell-Volhard Zelinsky (HVZ) reaction ?

Options

A. HCOOH
B. `CH_(3)COOH`
C. `CH_(3)CH_(2)COOH`
D. `CH_(3)CHBr COOH`

Explanation

To determine which of the given substances will not undergo the Hell-Volhard-Zelinsky (HVZ) reaction, we need to understand the requirements for this reaction to occur. The HVZ reaction is a halogenation reaction of carboxylic acids that requires the presence of alpha-hydrogens on the carbon adjacent to the carboxyl group.

### Step-by-Step Solution:

1. **Identify the Requirement for HVZ Reaction**:
The HVZ reaction requires at least one alpha-hydrogen on the carbon adjacent to the carboxylic acid group (the alpha-carbon).

2. **Analyze the Given Substances**:
For each substance, we need to check if there is an alpha-carbon with alpha-hydrogens present.

3. **Substance 1**:
If this substance has no alpha-carbon (i.e., the carbon next to the carboxylic acid group is not present), it cannot undergo the HVZ reaction.

4. **Substance 2**:
If this substance has an alpha-carbon with at least one alpha-hydrogen, it can undergo the HVZ reaction.

5. **Substance 3**:
Similar to substance 2, if this has an alpha-carbon with alpha-hydrogens, it can undergo the reaction.

6. **Substance 4**:
Check if this substance has an alpha-carbon with alpha-hydrogens. If it does, it can undergo the reaction.

7. **Conclusion**:
After analyzing all the substances, the one that lacks an alpha-carbon or has no alpha-hydrogens will be the one that does not undergo the HVZ reaction.

### Final Answer:
The substance that does not have any alpha-hydrogens or an alpha-carbon will not undergo the Hell-Volhard-Zelinsky (HVZ) reaction.