`[-NH(CH_(2))_(6) NHCO(CH_(2))_(4)CO-]_(n)` is a

Options

A. Thermosetting polymer
B. Homopolymer
C. Copolymer
D. Addition polymer

Explanation

To determine the identity of the polymer represented by the formula `[-NH(CH_(2))_(6)NHCO(CH_(2))_(4)CO-]_(n)`, we can follow these steps:

### Step 1: Analyze the Structure
The given structure can be broken down into its components. The repeating unit contains:
- An amine group (-NH-)
- A hexamethylene chain (6 carbon atoms)
- An amide linkage (NHCO)
- A butanedioic acid (4 carbon atoms)

### Step 2: Identify the Monomers
From the structure, we can identify the two monomers involved in the formation of this polymer:
1. **Hexamethylene diamine**: This is a compound with the formula H2N(CH2)6NH2, which contains two amine groups and a six-carbon chain.
2. **Adipic acid**: This is a dicarboxylic acid with the formula HOOC(CH2)4COOH, which contains a four-carbon chain and two carboxylic acid groups.

### Step 3: Understand the Polymerization Process
The polymerization occurs through a condensation reaction where:
- The amine groups from hexamethylene diamine react with the carboxylic acid groups from adipic acid.
- This reaction releases water (H2O) and forms amide bonds (-NHCO-).

### Step 4: Determine the Type of Polymer
Since the polymer is formed from two different types of monomers (hexamethylene diamine and adipic acid), it is classified as a **copolymer**.

### Step 5: Name the Polymer
The polymer formed from these two monomers is known as **Nylon 6,6**. The name comes from the fact that both monomers contribute 6 carbon atoms each to the polymer chain.

### Conclusion
The polymer represented by the formula `[-NH(CH_(2))_(6)NHCO(CH_(2))_(4)CO-]_(n)` is **Nylon 6,6**.

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