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A screw gauge has least count of 0.01 mm...

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale :
The pitch of the screw gauge is:

A

`0.25 mm`

B

`0.5 mm`

C

`1.0 mm`

D

`0.01 mm`

Text Solution

Verified by Experts

The correct Answer is:
B
Least count = `("Pitch")/("Number of division on circular scale")`
`implies 0.01 mm = ("Pitch")/(50)`
`implies ` pitch = `0.5 mm`.
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Knowledge Check

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