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Two cars P and Q start from a point at t...

Two cars `P` and `Q` start from a point at the same time in a straight line and their position are represented by `x_p(t) = at + bt^2` and `x_Q (t) = ft - t^2`. At what time do the cars have the same velocity ?

A

`(a+f)/(2(1+b))`

B

`(f-a)/(2(1+b))`

C

`(a-f)/(1+b)`

D

`(a+f)/(2(b-1))`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(X_(p)(t)=at+bt^(2),X_(Q)(t)=ft-t^(2)),(V_(p)=a+2bt,V_(Q)=f-2t):}`
as `V_(P)=V_(Q)`
`a+2bt=f-2t`
`impliest=(f-a)/(2(1+b))`
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