A body takes 4 minutes to cool from 100^...

A body takes 4 minutes to cool from `100^(@)C` to `70^(@)C`. To cool from `70^(@)C` to `40^(@)C` it will take (room temperture os `15^(@)C`)

A

7 minutes

B

6 minutes

C

5 minutes

D

4 minutes

Text Solution

Verified by Experts

The correct Answer is:

A

`(100-70)/(4)=K((100+70)/(2)-15)` …(i)
`(70-40)/(t)=K((70+40)/(2)-15)` …(ii)
Solving a. and b. t = 7 minute

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