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The distance between a proton and electr...

The distance between a proton and electron both having a charge `1.6xx10^(-19)` coulomb, of a hydrogen atom is `10^(-10)` metre . The value of intensity of electric field produced on electron due to proton will be

A

`14.4xx10^(14)N//C`

B

`12.2xx10^(14)N//C`

C

`11.4xx10^(14)N//C`

D

`13.2xx10^(14)N//C`

Text Solution

Verified by Experts

The correct Answer is:
A
`E=(Kq)/(r^(2))=(9xx10^(9)xx1.6xx10^(-19))/((10^(-12))^(2))`
`E=9xx10^(9)xx1.6xx10^(-19)xx10^(24)=14.4xx10^(14)N//C`
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