The electric field due to an electric dipole at a distance `r` from its centre in axial position is `E`. If the dipole is rotated through an angle of `90^(@)` about its perpendicular axis, the electric field at the same point will be

Options

A. E
B. `(E)/(4)`
C. `(E)/(2)`
D. 2E

Answer

C

Explanation

When a dipole AB very small length is taken , then for a point P located at a distance r from the axis the elctric field is given by
`E=(1)/(4piepsilon_(0))(2p)/(r^(3))` … (i)

Where , p is dipole moment ..When dipole is rotated by `90^(@)` , then electric field is given by

`E^(a)=(1)/(4piepsilon_(0))(p)/(r^(3))` .... (ii)
From Eqs (i) and (ii) , we get
`E=(E)/(2)`