The `500 muF` capacitor is charged at a steady rate of `100 mu C//s`. The potential difference across the capacitor will be 10 V after an interval of

Options

A. 80sec
B. 50sec
C. 20sec
D. 40sec

Answer

D

Explanation

Q=CV `rArr Q= 500 xx 10^(4) xx 10= 5000 xx 10^(-5)C` The time interval required to charge the capacitor to `5000 xx 10^(-6)C` will be equal to the one required for producing potential difference of 10V.
`T=(5000 xx 10^(-6))/(125 xx 10^(-6)) = 40` sec