Four capacitors `4mu F, 6mu F, 5mu F, 3mu F` are connected in series to a source of 150V. The potential difference in volt, the `5muF` capacitor will be

Options

A. 30volt
B. 40volt
C. 50 volt
D. 60 volt

Answer

A

Explanation

Equivalent capacitance `(1)/(C_(eq))= (1)/(C_(1)) + (1)/(C_(2)) + (1)/(C_(3)) + (1)/(C_(4))`
`(1)/(C_(eq))= (1)/(4) + (1)/(6) + (1)/(5) + (1)/(3)`
`(1)/(C_(eq))= (15+10+12+20)/(60)=(57)/(60)`
`C_(eq)=1.05 mu F`
`q=C_(eq)V`
`therefore q= 1.05 xx 10^(-6) xx 150=157.5 xx 10^(-6)`
`q=1.5 xx 10^(-4)C`
`therefore V=(q)/(C )=(1.5 xx 10^(-4))/(5 xx 10^(-6))=0.3 xx 10^(2)`
V=30 volt