Eight small drops, each of radius `r` and having same charge q are combined to form a big drop. The ratio between the potentials of the bigger drop and the smaller drop is

Options

A. `8:1`
B. `4:1`
C. `2:1`
D. `1:8`

Answer

B

Explanation

As we know that the potential of the big drop `V-= n^(2//3) V_(0)`
`V_(1)-= (8)^(2//3) V_(0)`
`V_(1)= 4V_(0)`
Potential of the smaller drops is V
`(V_(1))/(V_(0))= (4V_(0))/(V_(0)) = (4)/(1)= 4:1`