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As per this diagram a point charge +q is...

As per this diagram a point charge `+q` is placed at the origin `O`. Work done in taking another point charge `-Q` from the point `A(0, a)` to another point `B(a, 0)` along the staight path `AB` is:

A

zero

B

`(-qQ//4pi epsi 0) (1//a2) sqrt""2a`

C

`(qQ//4pi epsi 0) (1//a2) .a//sqrt""2`

D

`(qQ//4pi epsi 0) (1//a2) sqrt""2a`

Text Solution

Verified by Experts

The correct Answer is:
A

Work done= Change in potential energy `=q(Delta v)`
Here, Potential at point A and B are same. So, work done is equal to zero.
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