Find the charge on each of the capacitor 0.20ms after the switch S is closed in Figure.

Options

A. `24muC`
B. `16.8muC`
C. `10.37muC`
D. `4.5muC`

Answer

C

Explanation

`q=(q_(1))/(2) = (4 xx 10^(-6) xx 6)/(2) (1- e^((0.2 xx 10^(-3))/(4 xx 10^(-6) xx 25)))`
`q= 12 (1-e^(-2))mu C`
`12((e^(2)-1))/(e^(2)) mu C`
`=10.37mu C`