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A parallel plate copacitor is first char...

A parallel plate copacitor is first charged and then isolated, and a dielelctric slab is introduced between the plates. The quantity that remains unchanged is.

A

Charge Q

B

Potential V

C

Capacity C

D

Energy U

Text Solution

Verified by Experts

The correct Answer is:
A
Charge q remains unchanged when capacitor is the charged then dielectric slab is introduced between the plates.
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Knowledge Check

  • A parallel plate capacitor is charged and then isolated. On increasing the plate separation

    A
    `{:(" Charge Potential Difference Capacitance"),("remains constant remains constant decreases"):}`
    B
    `{:(" Charge Potential Difference Capacitance"),("remains constant increases decreases"):}`
    C
    `{:(" Charge Potential Difference Capacitance"),("remains constant decreases increases"):}`
    D
    `{:(" Charge Potential Difference Capacitance"),("increases decreases increases"):}`

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    B
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  • C,V,U and Q are capacitance, potential difference, energy stored and charge of parallel plate capacitor respectively. The quantities that increase when a dielectric slab is introduced between the plates without discounting the battery are

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