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In the circuit shown in the figure, the ...

In the circuit shown in the figure, the potential difference across the `4.5 muF` capacitor is

A

8/3 volt

B

4 volt

C

6volt

D

8volt

Text Solution

Verified by Experts

The correct Answer is:
D

`C_(eq)= 3+6=9mu F`
Then both capairor `4.5muF` becomes is series then As we know pot diffacross `45muR` capacity
`V= ((9)/(4.5 + 9))12=8V`
By the relation `V= ((9)/(4.5+9))12=8V`
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