If the capacitor shown in the circuit is charged to 5V and left in the circuit, in 12s the charge on the capacitor will become:

Options

A. `(10)/(e )` coulomb
B. `(e )/(10)` coulomb
C. `(10)/(e^(2))` coulomb
D. `(e^(2))/(10)` coulomb

Answer

A

Explanation

`q= q_(0)e^(-g//g)` where `q_(B)= CV=2 xx 5=10C`
`tau = CR=2 xx 6 =12s`
`q= 10e^(-(12)/(12))=(10)/(e )` Coulomb