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Fig shown below represents an area A = 0...

Fig shown below represents an area `A = 0.5 m^(2)` situated in a uniform magnetic field `B = 2.0 "weber"//m^(2)` and making an angle of `60^(@)` with respect to magnetic field.
The value of the magnetic flux through the area would be equal to

A

`2.0` weber

B

`sqrt(3)` weber

C

`3/2 ` weber

D

`0.5 ` weber

Text Solution

Verified by Experts

The correct Answer is:
D
`phi = BA cos theta`
`= 2.0 xx 0.5 xx cos 60^@`
`= 2.0 xx 0.5 xx 1/2 = 0.5 Wb`
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