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A beam of light travelling along x-axis ...

A beam of light travelling along x-axis is described by the magnetic field, `B_z=5xx10^-9Tsin omega (t-x//c)`
Calculating the maximum electric and magnetic forces on a charge, i.e alpha particle moving along y-axis with a speed of `3xx10^7m//s`, charge on electron =`1.6xx10^-19C`

A

`4.80 xx 10^(-17)N, 4.80 xx 10^(-17)N`

B

`4.85 xx 10^(-16)N, 5.6 xx 10^(-16)N`

C

`9.2 xx 10^(6)N, 9.2 xx 10^(3) N`

D

`4.8 xx 10^(-19) N, 4.8 xx 10^(-19) N`

Text Solution

Verified by Experts

The correct Answer is:
D
`B_(e ) = 5 xx 10^(-9) T`
`q=` Charge on `alpha-` particle `= 2 xx e`
Maximum electric field `E_(x) = c B`
`E _(x) = (3 xx 10^6) = ( 5 xx 10^(-3) ) `
`= 1.5 "Vm"^(-1)`
Maximum force on `alpha-` particle due to electric field
`F_(T ) = q xx E_(6)`
` = 3.2 xx 10^(-19) = 1.5`
`F_(E ) = 4.80 xx 10^(-19) N`
Maximum force on `alpha-` particle due to magnetic field
`F_(E ) = qv B`
`=3.2 xx 10^(-19) xx 3 xx 10^(3) xx 10^(-1) xx 5`
` F_(E ) = 4.80 xx 10^(-19) N`
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