In an electromagnetic wave, the electric and magnetising fields are 100 `"Vm"^(-1)` and 0.265 `"Am"^(-1)`. The maximum energy flow is

Options

A. `26.5 "W/m"^(2)`
B. `36.5"W/m"^2`
C. `46.7"Wm"^2`
D. `765 "W/m"^2`

Explanation

To find the maximum energy flow in an electromagnetic wave given the electric field \( E_0 \) and the magnetic field \( B_0 \), we can use the relationship between these fields and the intensity of the wave.

### Step-by-step Solution:

1. **Identify the given values**:
- Electric field \( E_0 = 100 \, \text{Vm}^{-1} \)
- Magnetic field \( B_0 = 0.265 \, \text{Am}^{-1} \)

2. **Understand the relationship between electric field, magnetic field, and intensity**:
- The intensity \( I \) of an electromagnetic wave is given by the product of the maximum electric field and the maximum magnetic field:
\[ I_{\text{max}} = E_0 \cdot B_0 \]

3. **Substitute the values into the formula**:
\[ I_{\text{max}} = 100 \, \text{Vm}^{-1} \times 0.265 \, \text{Am}^{-1} \]

4. **Calculate the maximum intensity**:
\[ I_{\text{max}} = 100 \times 0.265 = 26.5 \, \text{Wm}^{-2} \]

5. **Interpret the result**:
- The maximum energy flow (intensity) in the electromagnetic wave is \( 26.5 \, \text{Wm}^{-2} \).

### Final Answer:
The maximum energy flow in the electromagnetic wave is \( 26.5 \, \text{Wm}^{-2} \).