Two paricles have identical charges. If they are accelerated through identical potential differences, then the ratio of their deBrogile wavelength would be

Options

A. `lambda_(1) : lambda_(2) = 1 : 1`
B. `lambda_(1) : lambda_(2) = m_(2) : m_(1)`
C. `lambda_(1) : lambda_(2) = sqrt m_(2) : sqrt m_(1)`
D. `lambda_(1) : lambda_(2) = sqrt m_(2) : sqrt m_(1)`

Answer

C

Explanation

`lambda = (h)/(mV) = (h)/(sqrt (2m xx K.E))`
`lambda = (h)/(sqrt(2qVm)) = (lambda_(1))/(lambda_(1)) = sqrt((m_(2))/(m_(1)))`
as q and Volume (V) are same.