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The de - Broglie wavelength of a neutron...

The de - Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature `T ("kelvin")` and mass `m`, is

A

`(h)/(sqrt 3mkT)`

B

`(2h)/(sqrt 3mkT)`

C

`(2h)/(sqrt mkT)`

D

`(h)/(sqrt mkT)`

Text Solution

Verified by Experts

The correct Answer is:
A

At equilibrium thermal energy possessed by neutron `= (3)/(2) kT`
`lambda = (h)/(p) = (h)/(sqrt(2mE)) = (h)/(sqrt(2m(3)/(2)kT))`
`lambda = (h)/(sqrt(3m k T))`
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