Photons with energy 5 eV are incident on...

Photons with energy `5 eV` are incident on a cathode `C` in a photoelectric cell . The maximum energy of emitted photoelectrons is `2 eV`. When photons of energy `6 eV` are incident on `C` , no photoelectrons will reach the anode `A` , if the stopping potential of `A` relative to `C` is

`- 1 V`

`- 3 V`

`c, + 3V`

`+ 4 V`

Text Solution

Verified by Experts

The correct Answer is:

`e V_(3) = (1)/(2) m v_("max")^(2) = h v - phi_(0)`
`2 = 5 - phi_(0) rArr phi_(0) = 3 eV`
In second case
`eV_(3) = 6-3 = 3eV rArr V_(0) = 3V`
`therefore V_(AC) = -3V`

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Photons of energy 5 eV and incident on a cathode made of a photosensitive plate. The maximum kinetic energy of emitted photoelectrons is 3 eV . When photons of energy 8 eV fall on the same metal plate , the stopping potential of anode plate will be

`-7V`

`-6V`

3 V

`-3V`

Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV . The minimum kinetic energy of the emitted photo - electrons will be

`0 eV`

`1 eV`

`2 eV`

`10 eV`

A photon of energy 7 eV is incident on a metal surface having the work function of 3.75 eV. What is the stopping potential ?

2 V

3 V

3.25 V

4.5 V