A n-p-n transisitor is connected in common emitter configuration in a given amplifier. A load resistance of `800 Omega` is connected in the collector circuit and the voltage drop across it is `0.8 V`. If the current amplification factor is `0.96` and the input resistance of the circuits is `192 Omega`, the voltage gain and the power gain of the amplifier will respectively be

Options

A. 4,3,84
B. 3,69,3.84
C. 4,4d
D. 4,3.69

Answer

A

Explanation

Given (current amplification factor ) So,
`beta=alpha/(1-alpha)=0.96/0.04 to beta=24`
Voltage gain for common emitter configuration
`A_v= beta R_i/R_i=24{800/192}=100`
Power gain for common emitter configuraion
`P_v=betaA_f=24 times 100=2400`
Voltage gain for common base configuration
`A_v=alpha R_i/R_f=0.96 times 800/192=4`
Power gain for common base configuration
`P_v=A_v a=4 times 0.96=3.84`