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Trigonometric Ratios of Compound Angles#...

Trigonometric Ratios of Compound Angles#!#Sin(A+B)#!#Cos(A+B)#!#Sin(A-B)#!#Cos(A-B)

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Trigonometric ratios OF compound angle Sin(A+B) || Sin(A-B) || Cos(A+B) || Cos(A-B) and problem on these

2sin^(2)B+4cos(A+B)sin A sin B+cos2(A+B)=

(sin(A+B)+cos A-sin(A-B))/(cos(A-B)+sin A-cos(A+B))=

Cos A Cos B + Sin A Sin B

cos(A-D)sin(B-C)+cos(B-D)sin(C-A)+cos(C-D)sin(A-B)=0

Standard Formula sin(A+B) || sin(A–B) || cos(A+B) || cos(A–B)

Standard Formula sin(A+B) || sin(A–B) || cos(A+B) || cos(A–B)

Standard Formula sin(A+B) || sin(A–B) || cos(A+B) || cos(A–B)

Standard Formula sin(A+B) || sin(A–B) || cos(A+B) || cos(A–B)

Prove that: sin(B-C)cos(A-D)+sin(C-A)cos(B-D)+sin(A-B)cos(C-D)