What is the molarity of `H_(2)SO_(4)` solution which has a density 1.84 g/cc at `35^(@)C` and contains 98% by weight ?

Explanation

98% by mass means 98 g of `H_(2)SO_(4)` is present in 100g of acid.
Molarity, `M = ("Mass of solute" xx 1000)/("Molecular mass" xx "Volume")`
Mass of `H_(2)SO_(4) = 98 g`
Molecular mass of `H_(2)SO_(4) = 98 g mol^(-1)`
Volume of solution `= ("Mass")/("Density") = (100)/(1.84)`
Thus, molarity `= (98 xx 1000 xx 1.84)/(98 xx 100) = 18.4 M`