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(i) Define equivalent conductance and sp...

(i) Define equivalent conductance and specific conductance.
(ii) Discuss the effect of dilution on these conductances of an electrolyte.
(iii) The specific conductance of a decinormal solution of NaCl equals to `0.0092Omega^(-1)cm^(-1)`. If ionic conductance of `Na^(+) and Cl^(-)` ions are 43.0 and `65.0Omega^(-1)cm^(2)(g-eq)^(-1)` respectively. Calculate the degree of dissociation of NaCl solution.

Text Solution

Verified by Experts

Given,
Specific conductance = `0.0092Omega^(-1)cm^(-1)`
Ionic conductance of `Na^(+)=43.0Omega^(-1)cm^(-1)`
Ionic conductance = `Cl^(-)=65.0Omega^(-1)cm^(-1)`
Normality of NaCl = 0.1 N
`K(NaCl)=1(Na^(+))+1(Cl^(-))=43+65`
`108Omega^(-1)cm^(2)eq^(-1)`
Further, `wedge^(@)=kappaxx(1000)/(N)=(0.0092xx1000)/(0.1)`
`=92Omega^(-1)cm^(2)eq^(-1)`
Therefore, degree of dissociation `(alpha)=(92)/(108)=0.852`
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