`E^(@)` values for `Fe^(3+)+3e^(-)rarrFe` and `Fe^(2+)+2e^(-)rarrFe` are `-0.036V and -0.44V` respectively. Calculate the `E^(@)` and `DeltaG^(@)` for the cell reaction `Fe+2Fe^(3+)rarr3Fe^(2+)`.

Explanation

Given,
`Fe^(3+)+3e^(-)rarrFe" "E^(@)=-0.036V...(1)`
`Fe^(2+)+2e^(-)rarrFe" "E^(@)=-0.44V...(2)`
`Fe+2Fe^(2+)rarr3Fe^(2+)" "E^(@)=7,DeltaG^(@)=7`
On applying operation,
`(Eq(1)xx2)-(Eq(2)xx3)=Eq(3)`
`[-6xxFxx(-0.036)]-[-6xxFxx(-0.44)]=-6xxFxxE^(@)E^(@)=0.404V`
Now, `DeltaG^(@)` for Eq (3) is `-6xxFxx0.40V`
`=-6xx96500Cxx0.40V`
`=233916J=2339kJ`