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Find the boiling point of a solution co...

Find the boiling point of a solution containing 0.520 g glucose `(C_(6) H_(12) O_(6))` dissolved 80.2 g of water [Given , `K_(f)` for water `= 1.86 Km ^(-1)` ]

Text Solution

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Given `K_(b) = 0.52 Km^(-)`
Mass of solute `(W_(2))` = 0.520 g (glucose)
Mass of solute `(W_(1))` = 80.20 g (water)
Molar mass of solvent `(M_(2)) = 180 g mol^(-)`
Molar mass of solvent `(M_(1))= 18 g mol^(-1)`
`:. Delta T_(b) K_(b) xx (W_(2))/(M_(2)) xx (1000)/(W_(1))`
`Delta T_(b) = (0.52 xx 0.52 xx 1000)/(180 xx 80.2)`
`Delta T_(b) = 0.0187 = 0.019`
`:. ` Boiling point (b.p) = 373 + 0.019 = 373.019 K
Hence, boiling point of solution = 373.019 K
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