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Find the cartesian equation of a plane w...

Find the cartesian equation of a plane which is at a distance of 6 units from the origin and which has a normal with direction ratios (2, -1, -2).

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The correct Answer is:
`4hati - 2hatj + 4hatk` and coordinates are `(4, -2, 4)`
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ARIHANT PRAKASHAN-VERY SIMILAR TEST 9-Section B
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  4. A = [(1, 0), (0, 1)], B = [(1, 0), (0, -1)] and C = [(0, 1), (1, 0)], ...

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  5. Prove that abs[[b+c,c+a,a+b],[q+r,r+p,p+q],[y+z,z+x,x+y]]=2abs[[a,b,c]...

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  6. An urn contains 4 white and 6 red balls. Four balls are drawn at rando...

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  7. Using differentials, find approximate value (3.968)^(3//2)

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  10. If sin 2x = (2t)/(1 + t^(2)), tan y = (2t)/(1 - t^(2)) then find (dy)/...

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  11. Using mean value theorem, prove that sin xltx,in(0.pi//2).

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  12. Solve (dy)/(dx)+y=cos x-sin x

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  13. Find the equation of the curve passing through the point (1, 1) whose ...

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  14. Evaluate int(x^(2))/(x^(4)-x^(2)+12)dx.

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  15. Evaluate int(0)^(pi//2) (sin2x)/(sin^(4)x + cos^(4)x) dx.

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  18. Find the distance of the plane 2x - 3y + 4z - 6 = 0 from the origin an...

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  19. Prove that |veca xx vecb|^(2) = abs(veca)^(2)abs(vecb)^(2) - (veca * v...

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  20. Find the cartesian equation of a plane which is at a distance of 6 uni...

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