The distance between a proton and electron both having a charge `1.6 xx 10^(-19)C` of a hydrogne atom is `10^(-10)m`. The value of intensity of electric field produced on electron due to proton will be

Options

A. `2.304 xx 10^(-10)N//C`
B. 14.4V/m
C. 16V/m
D. `1.44 xx 10^(11)N//C`

Explanation

Given, `q= 1.6 xx 10^(-19), r= 10^(-10)m`
As we know that, electric field intensity,
`E= (q)/(4pi epsi_(0)r^(2))= 9 xx 10^(9) xx (1.6 xx 10^(-19))/((10^(-10))^(2))`
`=1.44 xx 10^(11)N//C`